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x^2+17x-200=0
a = 1; b = 17; c = -200;
Δ = b2-4ac
Δ = 172-4·1·(-200)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-33}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+33}{2*1}=\frac{16}{2} =8 $
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